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Algebra / Linear equations in one variable Difficulty: Easy

A rocket contained $467,000$ kilograms (kg) of propellant before launch. Exactly $21$ seconds after launch, $362,105$ kg of this propellant remained. On average, approximately how much propellant, in kg, did the rocket burn each second after launch?

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Explanation

Choice A is correct. It’s given that the rocket contained $467,000 kilograms left parenthesis kg right parenthesis$ of propellant before launch and had $362,105 kg$ remaining exactly $21$ seconds after launch. Finding the difference between the amount, in $kg$ , of propellant before launch and the remaining amount, in $kg$ , of propellant after launch gives the amount, in $kg$ , of propellant burned during the $21$ seconds: $467,000 - 362,105 = 104,895$ . Dividing the amount of propellant burned by the number of seconds yields $\frac{104,895}{21} = 4,995$ . Thus, an average of $4,995 kg$ of propellant burned each second after launch.

Choice B is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect and may result from conceptual or calculation errors.

Choice D is incorrect and may result from finding the amount of propellant burned, rather than the amount of propellant burned each second.